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SSC CGL Tier-II ( JSO ) 2019 Official Paper ( Held On : 17 Nov 2020 )

Option 2 : 10.4 ± 0.098

**Given**

n = sample = 64

sample mean = X̅ = 10.40

Z_{α/2} = 1.96

**Formula**

X̅ ∓ Z_{α/2}σ/√n

**Calculation**

⇒ 10.4 ± 1.96 × 0.4/√64

⇒ 10.4 ± 1.96 × 0.4/8

⇒ 10.4 ± 1.96 × 1/20

**∴ The 95% confidence interval is: 10.4 **±** 0.098**

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